Increasing the current sensitivity of a galvanometer may not necessarily increase its voltage sensitivity. Explain, giving reason.

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#### Solution

The current sensitivity of a moving coil galvanometer is given by `(nBA)/k`, where *n *is the number of turns , *A* is the area of the coil , *B* is the magnetic field strength of the poles and* k* is the spring's constant of the suspension wire.

Similarly, voltage sensitivity is given by `(nBA)/(kR)`, where *R *is the resistance of the wire.

From the above two expressions, we get:

Voltage sensitivity = Current sensitivity/*R*

Thus, on increasing the current sensitivity, voltage sensitivity may or may not increase because of similar changes in the resistance of the coil, which may also increase due to increase in temperature.

Concept: Moving Coil Galvanometer

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